3z^2+(1-6i)+2i=0

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Solution for 3z^2+(1-6i)+2i=0 equation:


Simplifying
3z2 + (1 + -6i) + 2i = 0

Remove parenthesis around (1 + -6i)
3z2 + 1 + -6i + 2i = 0

Reorder the terms:
1 + -6i + 2i + 3z2 = 0

Combine like terms: -6i + 2i = -4i
1 + -4i + 3z2 = 0

Solving
1 + -4i + 3z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -4i + -1 + 3z2 = 0 + -1

Reorder the terms:
1 + -1 + -4i + 3z2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4i + 3z2 = 0 + -1
-4i + 3z2 = 0 + -1

Combine like terms: 0 + -1 = -1
-4i + 3z2 = -1

Add '-3z2' to each side of the equation.
-4i + 3z2 + -3z2 = -1 + -3z2

Combine like terms: 3z2 + -3z2 = 0
-4i + 0 = -1 + -3z2
-4i = -1 + -3z2

Divide each side by '-4'.
i = 0.25 + 0.75z2

Simplifying
i = 0.25 + 0.75z2

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